Big ideas math algebra 1 page 191 answers

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  • Chapter 1 Solving Linear Equations
  • Chapter 2 Solving Linear Inequalities
  • Chapter 3 Graphing Linear Functions
  • Chapter 4 Writing Linear Functions
  • Chapter 5 Solving Systems of Linear Equations
  • Chapter 6 Exponential Functions and Sequences
  • Chapter 7 Polynomial Equations and Factoring
  • Chapter 8 Graphing Quadratic Functions
  • Chapter 9 Solving Quadratic Equations
  • Chapter 10 Radical Functions and Equations
  • Chapter 11 Data Analysis and Displays

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Chapter 4 - Writing Linear Functions - 4.3 - Writing Equations of Parallel and Perpendicular Lines - Exercises - Page 191: 8

Answer

Slopes of the lines $a$ and $b$ are same. So, they are parallel.

Work Step by Step

For line $a$: $3y-x=6$ $\implies 3y=6+x$ $\implies y=\frac{6+x}{3}=\frac{6}{3}+\frac{x}{3}$ $\implies y=\frac{1}{3}x+2$ Comparing the above equation with slope-intercept form $y=mx+b$, we find that the slope of line $a$=$\frac{1}{3}$ For line $b$: $3y=x+18$ $\implies y=\frac{x}{3}+\frac{18}{3}$ $\implies y=\frac{1}{3}x+6$ Comparing the above equation with slope-intercept form $y=mx+b$, we find that the slope of line $b$=$\frac{1}{3}$ For line $c$: $3y-2x=9$ $\implies 3y=2x+9$ $\implies y=\frac{2}{3}x+3$ Slope of line $c$= $\frac{2}{3}$ Slopes of the lines $a$ and $b$ are same. So, they are parallel.

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